Can memcpy given value as source address in c

WebApr 17, 2012 · I am trying to read two integers, stored consecutively, from a memory block (i have a pointer void *block pointing to the contents of the block) using memcpy. The first one is read just fine using: memcpy (&test, block, sizeof (int)); I try to read the second using: memcpy (&test, block + sizeof (int), sizeof (int)); (Of course i am having ... WebMar 12, 2013 · you can use memcpy as, memcpy(&req_byte, (buf+4), 1); this will copy fifth byte of your message to req_byte. you can vary number after (+) in source buffer to …

c - failure scenarios for memcpy - Stack Overflow

WebOct 11, 2024 · When you refer to the address of a pointer, this normally means the pointer's own location in memory, not the value it holds (which also is an address). – Andreas Wenzel Oct 11, 2024 at 4:55 1 @N001: If you follow the advice I gave in my first comment, does your program then work as intended? Both printed pointer values are the same, then. WebJun 24, 2015 · no, it's like *ptr = value;. memcpy takes the address of both source and destination. value must have type char * and ptr have type char ** (although you could … ion 3 amp ice auger https://ronrosenrealtor.com

how to implement overlap-checking memcpy in C - Stack Overflow

WebFeb 29, 2016 · You can just cast the char* to an int* and work with that seeing as you know you always have a valid 8-byte region to write to. char *data; … WebMar 12, 2016 · As Paul Ogilvie correctly explained, memcpy deals with user space addresses. As such they are virtual addresses, not necessarily physical addresses. Yet there is a possibility for very large areas with very specific alignment characteristics to optimize memcpy by requesting the OS to remap some of the destination virtual … WebSo the answer is no; the check is not necessary (or yes; you can pass zero). Share Improve this answer Follow edited Sep 22, 2012 at 10:42 answered Sep 20, 2010 at 13:32 Mike Seymour 248k 28 442 637 1 Would a pointer be considered "valid" for purposes of such a function if it pointed to the location following the last element of an array? i-on40h+

c - Using memcpy with hex values - Stack Overflow

Category:c++ - how to memcpy() a constant - Stack Overflow

Tags:Can memcpy given value as source address in c

Can memcpy given value as source address in c

Byte copying in C (using memcpy?) - Stack Overflow

WebAug 12, 2015 · In Win32 API programming it's typical to use C struct s with multiple fields. Usually only a couple of them have meaningful values and all others have to be zeroed out. This can be achieved in either of the two ways: STRUCT theStruct; memset ( &theStruct, 0, sizeof ( STRUCT ) ); or. STRUCT theStruct = {}; WebJun 18, 2016 · The type of the expression msg.data is different from the type of the expression &msg.data, but the values are identical. Since this is C++, the behavior is …

Can memcpy given value as source address in c

Did you know?

WebMar 28, 2013 · As a basic type safety check it makes sure the sizes of source and destination elements are the same. That's evaluated at compilation time as well. … WebApr 1, 2011 · I am trying to write a stl vector in C, and I could do it if client allocating memory on the heap and pass as an element to me. But I want it to work with basic datatype and there should not be special way to pass variables on the stack or heap variables. – Avinash Apr 5, 2011 at 13:33

WebNov 3, 2012 · First, memcpy () doesn't succeed or fail in the normal sense. It just copies the data, which might cause a fault/exception if it reads outside the source array or writes outside the destination array, and it might also read or write outside one of those arrays without causing any fault/exception and just silently corrupting data.

WebJun 4, 2013 · I need a function that stores data into a void pointer. Here is a simple example of it: void saveData (void* data) { char inputData [] = "some data"; memcpy ( (char*)data, inputData, sizeof (inputData)); } However I get segmentation errors when I do this, even though it compiles just fine. My function argument has to be a void pointer because I ... WebJul 11, 2013 · Understanding the source code of memcpy () 00018 void *memcpy (void *dst, const void *src, size_t len) 00019 { 00020 size_t i; 00021 00022 /* 00023 * memcpy …

WebApr 8, 2024 · Also remember that argument in C are passed by value, meaning the value is copied into the argument variable. Modifying the argument variable (like assigning to it) …

WebNov 20, 2014 · If you have allocated using malloc you must state the size of the array. int * src = malloc (ARRAY_LENGTH*sizeof (*src)); int * dst1 = malloc … ontario cycling road races 2022WebOct 21, 2014 · But memcpy () is about copying memory objects, not values. An object resides at a given address, and contains a given value. Taking n gives the value, … ontario daily epidemiologic summaryWebJan 22, 2024 · Some (most) implementations of memcpy() assume that it can copy data in one specific direction which will cause data to be corrupted if areas overlap in the wrong way (e.g. if the implementation uses the "lowest address first" direction and the destination area overlaps and is at a higher address than the source, then writes to the destination ... ontario daily court listingWebJan 21, 2016 · Define you own memcpy to copy to this address space : void my_memcpy( ptr8 addr_dest, const void * src, int len ) { memcpy( my_destination_memory + … ontario dachshund rescue organizationWebApr 29, 2004 · Optimizing Memcpy improves speed. Knowing a few details about your system-memory size, cache type, and bus width can pay big dividends in higher performance. The memcpy () routine in every C … ion 4WebJan 7, 2016 · memcpy () is used to copy a block of memory from a location to another. It is declared in string.h // Copies "numBytes" bytes from address "from" to address "to" void * memcpy (void *to, const void *from, size_t numBytes); Below is a sample C program to … Before memset(): GeeksForGeeks is for programming geeks. After memset(): … ontario daily court casesWebMay 28, 2009 · which is actually just the reverse of the memcpy () you did to get the pointer there in the first place. Although, treating the pointer as an int: int addressOfArgTwo = (unsigned int)buff; is also dangerous, if you're moving between 32-bit and 64-bit architectures, as Michael pointed out. Pointers aren't always 32-bit integers. ontario cycling association results